CC BY 4.0 （除特别声明或转载文章外）
如果这篇博客帮助到你，可以请我喝一杯咖啡~
Jin Yong’s Wukong Ranking List
#include <bits/stdc++.h>
#define maxn 1000
using namespace std;
int head[maxn], tot, n, numofp;
struct edge
{
int to, next;
} e[maxn << 2];
inline void addedge(int u, int v)
{
e[++tot].next = head[u];
e[tot].to = v;
head[u] = tot;
}
bool find(int a, int b)
{
queue<int> q;
bool ed[100] = {0};
q.push(a);
ed[a] = 1;
while (!q.empty())
{
int u = q.front();
q.pop();
for (int i = head[u]; i; i = e[i].next)
{
if (e[i].to == b)
return true;
if (!ed[e[i].to])
q.push(e[i].to);
}
}
return false;
}
string a[maxn];
map<string, int> mp;
int main(void)
{
while (~scanf("%d", &n))
{
memset(head, 0, sizeof(head));
tot = 0;
mp.clear();
for (int i = 1; i <= n; i++)
{
cin >> a[i * 2 - 1] >> a[i * 2];
}
bool ok = 1;
for (int i = 1; i <= n; i++)
{
int p1, p2;
if (mp.count(a[i * 2 - 1]))
p1 = mp[a[i * 2 - 1]];
else
p1 = mp[a[i * 2 - 1]] = ++numofp;
if (mp.count(a[i * 2]))
p2 = mp[a[i * 2]];
else
p2 = mp[a[i * 2]] = ++numofp;
// cout<<p1<<" "<<p2<<endl;
if (find(p2, p1))
{
cout << a[i * 2 - 1] << " " << a[i * 2] << endl;
ok = 0;
break;
}
addedge(p1, p2);
}
if (ok)
cout << "0\n";
}
//system("pause");
}
Heshen’s Account Book
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int maxn = 1000 + 10;
int nL, n, tot, lin[maxn], c[maxn];
LL ans[maxn];
char ch[maxn], s[maxn], last[maxn];
bool check()
{
if (nL == 0)
return false;
for (int i = 1; i <= nL; i++)
if ('a' <= s[i] && s[i] <= 'z')
return false;
int num = 0;
for (int i = 1; i <= nL; i++)
if (s[i] == '0')
num++;
else
break;
if (num > 1 || num == 1 && nL != 1)
return false;
return true;
}
LL made()
{
LL res = 0;
for (int i = 1; i <= nL; i++)
res = res * 10ll + (LL)(s[i] - '0');
return res;
}
void next()
{
if (check())
{
ans[tot] = made();
lin[c[tot]]++;
tot++;
}
nL = 0;
c[tot] = maxn;
}
int main()
{
while (fgets(ch, maxn, stdin))
{
n++;
int L = strlen(ch);
if (!(isdigit(ch[0]) && isdigit(last[n - 1])))
next();
for (int i = 0; i < L; i++)
{
if (ch[i] == ' ')
next();
else if (ch[i] != '\n')
{
s[++nL] = ch[i];
c[tot] = min(c[tot], n);
}
if (ch[i] != '\n')
last[n] = ch[i];
}
}
next();
if (tot != 0)
{
for (int i = 0; i < tot - 1; i++)
printf("%lld ", ans[i]);
printf("%lld\n", ans[tot - 1]);
}
for (int i = 1; i <= n; i++)
printf("%d\n", lin[i]);
}
Frog and Portal
#include <bits/stdc++.h>
#define ll long long
using namespace std;
ll fib[200];
int find(ll val)
{
return upper_bound(fib, fib + 55, val) - fib - 1;
}
int main(void)
{
fib[0] = fib[1] = 1;
for (int i = 2; i <= 60; i++)
fib[i] = fib[i - 1] + fib[i - 2];
ll a;
while (cin >> a)
{
if (a == 0)
{
cout << "2\n1 1\n2 1\n";
continue;
}
int loc = 0, loc2 = 150;
vector<int> vec;
vec.clear();
while (a)
{
ll tem = find(a);
//cout<<tem<<endl;
//cout<<fib[tem]<<endl;
vec.push_back(loc + 1);
vec.push_back(loc2 - tem);
//cout<<loc+1<<" "<<loc2-tem<<endl;
loc += 2;
//cout<<loc2+tem<<" "<<199<<endl;
//cout<<loc2+tem+1<<" "<<loc2+tem+1<<endl;
//loc2+=tem+2;
a -= fib[tem];
}
printf("%d\n", vec.size() / 2 + 3);
for (int i = 0; i < vec.size(); i += 2)
cout << vec[i] << " " << vec[i + 1] << endl;
cout << loc << " " << loc << endl;
cout << 150 << " " << 199 << endl;
cout << 151 << " " << 151 << endl;
}
//system("pause");
}
Approximate Matching
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int maxn = 50;
int T, n, m;
LL f[maxn][maxn * maxn];
char ch[maxn];
struct Trie
{
int next[maxn * maxn][2], fail[maxn * maxn], end[maxn * maxn];
int root, L;
int newnode()
{
for (int i = 0; i < 2; i++)
next[L][i] = -1;
end[L++] = 0;
return L - 1;
}
void init()
{
L = 0;
root = newnode();
}
void insert(char *buf)
{
int L = strlen(buf), now = root;
for (int i = 0; i < L; i++)
{
if (next[now][buf[i] - '0'] == -1)
next[now][buf[i] - '0'] = newnode();
now = next[now][buf[i] - '0'];
}
end[now]++;
}
void build()
{
queue<int> Q;
fail[root] = root;
for (int i = 0; i < 2; i++)
if (next[root][i] == -1)
next[root][i] = root;
else
{
fail[next[root][i]] = root;
Q.push(next[root][i]);
}
while (!Q.empty())
{
int now = Q.front();
Q.pop();
for (int i = 0; i < 2; i++)
if (next[now][i] == -1)
next[now][i] = next[fail[now]][i];
else
{
fail[next[now][i]] = next[fail[now]][i];
Q.push(next[now][i]);
}
}
}
} tree;
int main()
{
scanf("%d", &T);
while (T--)
{
tree.init();
scanf("%d%d", &n, &m);
scanf("%s", ch);
if (n > m)
{
printf("0\n");
continue;
}
else if (n == m)
{
printf("%d\n", n + 1);
continue;
}
tree.insert(ch);
for (int i = 0; i < n; i++)
{
if (ch[i] == '0')
ch[i] = '1';
else
ch[i] = '0';
tree.insert(ch);
if (ch[i] == '0')
ch[i] = '1';
else
ch[i] = '0';
}
tree.build();
memset(f, -1, sizeof(f));
f[0][0] = 1;
for (int i = 1; i <= m; i++)
{
for (int j = 0; j < tree.L; j++)
{
if (f[i - 1][j] == -1 || tree.end[j])
continue;
for (int k = 0; k < 2; k++)
{
int son = tree.next[j][k];
if (tree.end[son])
continue;
if (f[i][son] == -1)
f[i][son] = f[i - 1][j];
else
f[i][son] += f[i - 1][j];
}
}
}
LL ans = 0;
for (int j = 1; j < tree.L; j++)
if (f[m][j] > 0)
ans += f[m][j];
printf("%lld\n", (1ll << m) - ans);
}
}
Palindromes
#include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 9;
struct Wint : deque<int> //继承vector
{
static const int width = 1, base = 1e1;
Wint(unsigned long long n = 0) //普通初始化，当整型数和Wint同时运算时会提升至Wint
{
for (; n; n /= base)
push_back(n % base);
}
explicit Wint(const string &s) //字符串初始化函数，未判断字符串合法情况
{
for (int len = int(s.size() - 1) / width + 1, b, e, i = 0; i < len; ++i)
for (e = s.size() - i * width, b = max(0, e - width), push_back(0); b != e; ++b)
back() = back() * 10 + s[b] - '0';
trim(0);
}
Wint &trim(bool up = 1) //去前导0，是否需要进位，很常用的小函数，为方便返回自身
{
for (int i = 1; up && i < size(); ++i)
{
if ((*this)[i - 1] < 0)
--(*this)[i], (*this)[i - 1] += base;
if ((*this)[i - 1] >= base)
(*this)[i] += (*this)[i - 1] / base, (*this)[i - 1] %= base;
}
while (!empty() && back() <= 0)
pop_back();
for (; up && !empty() && back() >= base; (*this)[size() - 2] %= base)
push_back(back() / base);
return *this;
}
friend istream &operator>>(istream &is, Wint &n)
{
string s; //懒
return is >> s, n = Wint(s), is;
}
friend ostream &operator<<(ostream &os, const Wint &n)
{
if (n.empty())
return os.put('0');
os << n.back();
char ch = os.fill('0');
for (int i = n.size() - 2; ~i; --i)
os.width(n.width), os << n[i];
return os.fill(ch), os;
}
friend bool operator<(const Wint &a, const Wint &b)
{
if (a.size() != b.size())
return a.size() < b.size();
for (int i = a.size() - 1; ~i; --i)
if (a[i] != b[i])
return a[i] < b[i];
return 0;
}
friend bool operator>(const Wint &a, const Wint &b) { return b < a; }
friend bool operator<=(const Wint &a, const Wint &b) { return !(a > b); }
friend bool operator>=(const Wint &a, const Wint &b) { return !(a < b); }
Wint &operator+=(const Wint &b)
{
if (size() < b.size())
resize(b.size()); //保证有足够的位数
for (int i = 0; i < b.size(); ++i)
(*this)[i] += b[i];
return trim(); //单独进位防自运算
}
friend Wint operator+(Wint a, const Wint &b) { return a += b; }
Wint &operator++() { return *this += 1; } //前置版本，懒
Wint operator++(int) //后置版本
{
Wint b(*this);
return ++*this, b;
}
Wint &operator-=(const Wint &b) //a<b会使a变为0
{
if (size() < b.size())
resize(b.size()); //保证有足够的位数
for (int i = 0; i < b.size(); ++i)
(*this)[i] -= b[i];
return trim(); //单独进位防自运算
}
friend Wint operator-(Wint a, const Wint &b) { return a -= b; }
Wint &operator--() { return *this -= 1; } //前置版本，懒
Wint operator--(int) //后置版本
{
Wint b(*this);
return --*this, b;
}
Wint &operator*=(const Wint &b) //高精度乘法，常规写法
{
Wint c;
c.assign(size() + b.size(), 0);
for (int j = 0, k, l; j < b.size(); ++j)
if (b[j]) //稀疏优化，特殊情况很有效
for (int i = 0; i < size(); ++i)
{
unsigned long long n = (*this)[i];
for (n *= b[j], k = i + j; n; n /= base)
c[k++] += n % base;
for (l = i + j; c[l] >= base || l + 1 < k; c[l++] %= base)
c[l + 1] += c[l] / base;
}
return swap(c), trim(0);
}
/*
Wint& operator*=(const Wint &b)//一种效率略高但对位宽有限制的写法
{
vector<unsigned long long> n(size()+b.size(),0);//防爆int
//乘法算完后统一进位效率高，防止乘法溢出（unsigned long long范围0~1.8e19）
//位宽为9时size()不能超过18（十进制162位），位宽为8时size()不能超过1800（十进制14400位）等等。
for(int j=0; j!=b.size(); ++j)
if(b[j])//稀疏优化，特殊情况很有效
for(int i=0; i!=size(); ++i)
n[i+j]+=(unsigned long long)(*this)[i]*b[j];
for(int i=1; i<n.size(); ++i)//这里用<防止位数0，单独进位防自运算
n[i]+=n[i-1]/base,n[i-1]%=base;
return assign(n.begin(),n.end()),trim(0);
}
Wint& operator*=(const Wint &b)//fft优化乘法，注意double仅15位有效数字，调小Wint::width不超过2，计算自2*log2(base)+2*log2(len)<53
{
vector<ll> ax(begin(),end()),bx(b.begin(),b.end());
ax=FFT(size()+b.size()).ask(ax,bx);
for(int i=1; i<ax.size(); ++i)
ax[i]+=ax[i-1]/base,ax[i-1]%=base;
return assign(ax.begin(),ax.end()),trim(0);
}
Wint& operator*=(const Wint &b)//ntt优化，Wint::width不超过2
{
vector<ll> ax(begin(),end()),bx(b.begin(),b.end());
ax=FNTT(size()+b.size(),(7<<26)+1,3).ask(ax,bx);
for(int i=1; i<ax.size(); ++i)
ax[i]+=ax[i-1]/base,ax[i-1]%=base;
return assign(ax.begin(),ax.end()),trim(0);
}
*/
friend Wint operator*(Wint a, const Wint &b) { return a *= b; }
Wint &operator/=(Wint b)
{
Wint r, c, d = b.base / (b.back() + 1);
*this *= d, b *= d, c.assign(size(), 0);
for (int i = size() - 1; ~i; --i)
{
r.insert(r.begin(), (*this)[i]);
unsigned long long s = 0;
for (int j = b.size(); j + 1 >= b.size(); --j) //b.size()==0肯定第一行就出问题的
s = s * b.base + (j < r.size() ? r[j] : 0);
for (d = c[i] = s / b.back(), d *= b; r < d; r += b)
--c[i];
r -= d;
}
return swap(c), trim(0); //r为加倍后的余数，可通过高精度除低精度得到真正余数，此处略
}
friend Wint operator/(Wint a, const Wint &b) { return a /= b; }
Wint &operator%=(const Wint &b) { return *this -= *this / b * b; }
friend Wint operator%(Wint a, const Wint &b) { return a %= b; }
//开平方，改自ZJU模板
bool cmp(long long c, int d, const Wint &b) const
{
if ((int)b.size() - (int)size() < d + 1 && c)
return 1;
long long t = 0;
for (int i = b.size() - 1, lo = -(base << 1); lo <= t && t <= 0 && ~i; --i)
if (t = t * base - b[i], 0 <= i - d - 1 && i - d - 1 < size())
t += (*this)[i - d - 1] * c;
return t > 0;
}
Wint &sub(const Wint &b, long long k, int d)
{
int l = b.size() + d;
for (int i = d + 1; i <= l; ++i)
{
long long tmp = (*this)[i] - k * b[i - d - 1];
if (tmp < 0)
{
(*this)[i + 1] += (tmp - base + 1) / base;
(*this)[i] = tmp - (tmp - base + 1) / base * base;
}
else
(*this)[i] = tmp;
}
for (int i = l + 1; i < size() && (*this)[i] < 0; ++i)
{
(*this)[i + 1] += ((*this)[i] - base + 1) / base;
(*this)[i] -= ((*this)[i] - base + 1) / base * base;
}
return trim(0);
}
friend Wint sqrt(Wint a)
{
Wint n;
n.assign(a.size() + 1 >> 1, 0);
for (int i = n.size() - 1, l, r; ~i; --i)
{
for (l = 0, r = a.base, n[i] = l + r >> 1; r - l > 1; n[i] = l + r >> 1)
{
if (n.cmp(n[i], i - 1, a))
r = n[i];
else
l = n[i];
}
a.sub(n, n[i], i - 1), n[i] += l + r >> 1;
}
for (int i = 0; i < n.size(); ++i)
n[i] >>= 1;
return n.trim(0);
}
/*
friend Wint sqrt(const Wint &a)//常规牛顿迭代实现的开平方算法，慢但是好敲
{
Wint b=a,c=(b+1)/2;
while(b!=c)swap(b,c),c=(b+a/b)/2;
return c;
}
friend Wint sqrt(const Wint &a)
{
Wint ret,t;
ret.assign((a.size()+1)>>1,0);
for(int i=ret.size()-1,l,r; ~i; --i)
{
for(l=0,r=a.base; r-l>1;)
{
ret[i]=l+(r-l)/2;
t=ret*ret;
if(a<t)r=ret[i];
else l=ret[i];
}
if(!l&&i==ret.size()-1)ret.pop_back();
else ret[i]=l;
}
return ret;
}
*/
};
int t;
int main()
{
for (cin >> t; t--;)
{
Wint k;
cin >> k;
if (k == Wint(1))
{
cout << "0\n";
continue;
}
k -= 1;
int odd = 1;
for (Wint p = 9, val = 0, tmp0 = 0, tmp1 = 0, tk = k / 2;;)
{
if (odd)
tmp1.push_front(9);
else
tmp0.push_front(9);
if (tk <= tmp1)
if (k <= tmp0 + tmp1)
{
val += k + p - tmp0 - tmp1;
ostringstream sout;
sout << val;
string s = sout.str();
cout << s;
if (odd)
s.erase(s.size() - 1);
reverse(s.begin(), s.end());
cout << s << '\n';
break;
}
if (odd ^= 1)
{
val.push_front(9);
p.push_front(0);
}
}
}
}